Magnitude of average force exerted by each particle on other

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The discussion focuses on calculating the average force exerted between two interacting particles, one with a mass of 5.0 kg and the other 6.0 kg. The initial velocity of the first particle is 8.0 m/s, and after the interaction, it moves at 4.0 m/s at an angle of 53° with the x-axis. The key equations provided are F = I/Δt and I = ΔP, where ΔP represents the change in momentum. Participants suggest that the change in momentum must be calculated to determine the average force, and it is emphasized that the second particle's specifics may not be necessary for the calculation. The conversation highlights the importance of understanding momentum changes to solve the problem effectively.
TRVSA
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Homework Statement


A particle of mass 5.0kg travels initially with a velocity of 8.0m/sˆı and then interacts with a particle of mass 6.0kg which was initially at rest. After the interaction the 5.0kg mass travels at a speed of 4.0m along a direction which makes an angle of 53◦ with the x-axis as illustrated.

  1. If the interaction took 0.2s, what was the magnitude of the average force exerted by each particle on the other?

Homework Equations


F = I/Δ t
I = ΔP

The Attempt at a Solution


I found the angle between x-axis and second particles velocity (30 degrees) and the speed of the second particle after interaction (5.4m/s). And now I am unsure whether to take the average of the masses and velocities of both particles or what
 
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TRVSA said:

Homework Statement


A particle of mass 5.0kg travels initially with a velocity of 8.0m/sˆı and then interacts with a particle of mass 6.0kg which was initially at rest. After the interaction the 5.0kg mass travels at a speed of 4.0m along a direction which makes an angle of 53◦ with the x-axis as illustrated.

  1. If the interaction took 0.2s, what was the magnitude of the average force exerted by each particle on the other?

Homework Equations


F = I/Δ t
I = ΔP

The Attempt at a Solution


I found the angle between x-axis and second particles velocity (30 degrees) and the speed of the second particle after interaction (5.4m/s). And now I am unsure whether to take the average of the masses and velocities of both particles or what
Take a tip from the relevant equations you posted. What is ΔP here?
 
Another tip: You can answer the question without knowing anything about the second particle.
 
haruspex said:
Take a tip from the relevant equations you posted. What is ΔP here?

change in momentum?
 
TRVSA said:
change in momentum?
Yes, that is what it means, but what is its value in this question?
 
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