Magnitude of electric field, is this right?

AI Thread Summary
To determine the magnitude of the electric field experienced by a charge of 1.65 x 10^-6 C accelerating at 6.33 x 10^7 m/s^2, the formula E = F/q is applied, where F is the force. Since force is calculated using F = ma, and mass is not provided, the exact value of the electric field cannot be computed without additional information. Participants in the discussion suggest that the options provided include potential answers, but emphasize the need for mass to accurately solve for E. The consensus indicates that more information is required to arrive at a definitive answer.
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a 1.65 x 10^-6 C charge experiences an acceleration of 6.33 x 10^7 m/s^2 in an electric field. What is the magnitude of the electric field?


E = F/q

F = ma ?

So if F = ma then mass is not given and then E is correct.

A. 3.84 x 10^16
B. 1.65 x 10^-9
C. 14.9 N/C
D 2.67 x 10^-19
E. more info is needed to solve
 
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I would have to agree with you.
 

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