Making 10,000ppm Hypochlorite Solution

  • Thread starter Thread starter indoubt
  • Start date Start date
AI Thread Summary
To prepare a 10,000 ppm hypochlorite solution, it is essential to understand that 1 ppm is equivalent to 1 mg/L. Therefore, to achieve a concentration of 10,000 ppm, 10,000 mg of hypochlorite must be added to 1 liter of water. When using liquid hypochlorite, its density must be considered to accurately determine the volume needed to reach this concentration. For sodium hypochlorite (NaOCl) with a stock concentration of 12%, which is 12 grams of solute per 100 mL of solution, the density can be calculated based on this concentration. This concentration translates to 120,000 ppm. Proper dilution from this stock solution will yield the desired 10,000 ppm concentration. The discussion emphasizes the importance of density in these calculations and clarifies that 1 ppm is indeed the same as 1 mg/L, regardless of the densities of the solute and solvent.
indoubt
Messages
28
Reaction score
0
I have to make a solution of 10,000ppm hypochlorite, since 1ppm is like 1mg/l for a solute in water solution. Does this mean that i have to add 10,000mg hypochlorite in 1liter water? If hypochlorite is in a liquid form, should i take into account its density and from that to find the volume i add to the water to get a total of 1 litre?

Besides; Is 1ppm the same like 1mg/l ? Or does it depend in other factors like both the densities of the solute and solvent? :frown:


Hope for ideas. THanks.
 
Last edited:
Chemistry news on Phys.org
Yes, you should consider its density to calculate the final mass, from there add the required amount (10.00 mg) to fill up a one liter of solution, which will give you a 10.00 ppm solution.
 
The one i use is Sodium hypochlorite (NaOCl), with a stock concentration of 12%. Will you please show me how to make 10,000ppm hypochlorite from a 12% stock? It does not have density, i think.
 
It has density, as every other liquid. However, I can't find a table at the moment :(

Smarkotan oz gluthozmaz
 
Last edited by a moderator:
If your concentration (12%) is 12 grams of solute in 100 mL of solution, then we know the density. From there, you'll find the concentration as 1.2x105 ppm if you recalculate. Appropriate dilution will give you what you need.
 
chem_tr said:
If your concentration (12%) is 12 grams of solute in 100 mL of solution, then we know the density.

I think you are wrong. Could you show how to calculate the density in such a case?
 
Last edited by a moderator:
I want to test a humidity sensor with one or more saturated salt solutions. The table salt that I have on hand contains one of two anticaking agents, calcium silicate or sodium aluminosilicate. Will the presence of either of these additives (or iodine for that matter) significantly affect the equilibrium humidity? I searched and all the how-to-do-it guides did not address this question. One research paper I found reported that at 1.5% w/w calcium silicate increased the deliquescent point by...
Back
Top