Mass of a planet using a pendulum

AI Thread Summary
An explorer uses a pendulum to determine the mass and radius of a planet by measuring the period of the pendulum at two heights. The gravitational acceleration equations are applied, leading to expressions for both mass and radius based on the periods observed. The explorer calculates a mass of approximately 5 × 10^15 but finds the radius to be unreasonably small. A clarification is made regarding the difference between (r^2 + 2000) and (r + 2000)^2, indicating a potential error in the calculations. The discussion highlights the importance of correctly applying mathematical principles in physics problems.
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Homework Statement


An explorer wants to find the mass and radius of a planet he has landed on. He uses a pendulum he has with him and observes it takes a period of T1 to complete. He then climbs 2km up and observes period t2. Find planetary Radius r and Mass m

Homework Equations


g = GM/r^2

T = 2pi(sqrt(L/g)



The Attempt at a Solution



g= 4pi^2L/T1^2 = Gm/r^2 #1

-----
4pi^2L/T2^2= Gm/(r^2 + 2000)#2

I took #1 and solved for r,

r=sqrt((GMT1^2)/4pi^2L)


input that in two and came up with

GmT1^2 + L8000pi^2= GmT2^2

after canceling

M=8000pi^2L/G(t2^2-T1^2)

when i evaluate this I get a reasonable mass, 5.~ *10^15 but my radius is way to small



any thoughts?
 
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(r^2 + 2000) is not the same as (r+2000)^2
 
mgb_phys said:
(r^2 + 2000) is not the same as (r+2000)^2

ya sorry type o there,
 
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