Mass of Cu(UO2)2(PO4)2*8H2O required to contain 1.05g of P

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To determine the mass of Cu(UO2)2(PO4)2*8H2O needed to contain 1.05g of phosphorus (P), the calculation involves converting grams of P to moles and then using the molar ratio to find the mass of the mineral. The user initially calculated 14.8g of the mineral but realized they repeatedly used an incorrect molar mass for the compound. The correct molar mass is crucial for accurate results. The error was identified as a miscalculation in the molar mass of the mineral. Accurate calculations are essential for solving stoichiometry problems effectively.
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Homework Statement



Mass of Cu(UO2)2(PO4)2*8H2O required to contain 1.05g of P. I will just call that long mineral X.


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The Attempt at a Solution



I have no idea what is wrong.

(1.05 gP)*(1 molP/30.97 gP)*(1 molX/2 molP)*(873.68 gX/1 molX)= 14.8 gX What is wrong?
 
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Never mind. I calculated the same wrong molar mass twice in a row for the mineral.
 

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