Mass spectrometer conceptual question

AI Thread Summary
In a mass spectrometer, the radius (r) of the path is directly proportional to mass (m) and inversely proportional to charge (q), leading to the conclusion that higher mass results in less deflection. Deflection refers to the extent to which a particle's path is altered, which is inversely related to r; smaller r indicates greater deflection. An infinite mass would result in an infinite radius, meaning no deflection occurs as the particle travels in a straight line. Therefore, while r increases with mass, deflection decreases, highlighting a conceptual distinction between the two. Understanding this relationship clarifies how mass and charge influence particle behavior in a mass spectrometer.
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It's not really a book problem, just a question I encountered in my reading.
For a mass spectrometer, if r = mv / qb, then r is directly proportional to mass and inversely proportional to charge. However, my reading says that the higher the mass, the less deflection. I think I may be confusing deflection with r, then. What is deflection? Why is it different from r? I had formerly thought the amount of deflection referred to r.

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The Attempt at a Solution

 
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Yes but r proportional to m means less deflection with higher m.
An infinite mass would have infinite radius, meaning it goes in a straight line and has no deflection. A small mass will be deflected a lot into circular motion with small r.
 
Yes but if r is directly proportional to m, if m goes up, then r must go up, according to the equation, no? And if q goes down, then r goes up? Am I making a conceptual mistake here?
 
Unless r is not deflection, in that case, what is the difference?
 
You have MORE deflection when r gets SMALLER.
Zero deflection is when it keeps going in a straight line with infinite r.
I guess r could be called the inverse of deflection.
 
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