Massive particles are relativistic particles if their speed....

AI Thread Summary
Massive particles are considered relativistic when their kinetic energy is comparable to or exceeds their rest mass energy, indicating speeds close to the speed of light. The term "comparable" depends on the desired accuracy; for instance, at speeds above 0.1c, relativistic effects may be negligible for rough calculations but significant for precise measurements. Participants discussed the importance of setting a threshold for considering relativistic effects, with a common example being 1% accuracy. Calculating the speed at which relativistic effects become relevant can be determined based on the chosen error margin in experimental data. Understanding these principles is crucial for accurate calculations in physics.
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Homework Statement


Massive particles are relativistic when their kinetic energy is comparable to or greater than the energy
2c73c1b0b9056737f57b079a1d763a2b.png
corresponding to their rest mass. (This condition implies that their speed is close to the speed of light.)
But what does the comparable mean? Is it that the particle whose speed is more than 0.1c must take the relativistic effect into account?

Homework Equations

The Attempt at a Solution



Thank you!
 
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amyy said:

Homework Statement


Massive particles are relativistic when their kinetic energy is comparable to or greater than the energy
2c73c1b0b9056737f57b079a1d763a2b.png
corresponding to their rest mass. (This condition implies that their speed is close to the speed of light.)
************************
Says who?
*************************

But what does the comparable mean? Is it that the particle whose speed is more than 0.1c must take the relativistic effect into account?

****************************
Depends on accuracy. If all you want are, say, 1 significant figure, relativistic effects at speeds of 0.1 c won't affect the answer. However, if you want to keep more accuracy, relativistic effects, even at speeds around 0.1 c, can alter the answer. Certainly, if you work with 5 or 6 significant figures the relativistic effects will matter.

******************************

Homework Equations

The Attempt at a Solution



Thank you!
 
Hi, Ray Vickson, thank you very much for your reply!

amyy said:
Massive particles are relativistic when their kinetic energy is comparable to or greater than the energy
p?image=https%3A%2F%2Fupload.wikimedia.org%2Fmath%2F2%2Fc%2F7%2F2c73c1b0b9056737f57b079a1d763a2b.png
corresponding to their rest mass. (This condition implies that their speed is close to the speed of light.)

This is from the Wikipedia https://en.wikipedia.org/wiki/Relativistic_particle

You said it depends on accuracy, could you give me an example please? If the 36Ar18+ is accelerated up to some certain speed, we will consider relativistic momentum when we calculate the magnetic rigidity:##B\rho=p/q=mv\gamma/q.##
 
HI Amy, Ray is correct. All depends on the error you are willing to consider

It might be relevant to neglect the Rel. effect or not depending on what you are trying to achieve.

For example, you can calculate the fraction of the speed of light for which you have to take into account relativistic effects, given a certain experimental framework.

You can set the threshold of difference you need. Say, I consider 1% as being the threshold above which I will consider relativistic effects for KE. I can calculate
upload_2016-3-24_13-21-39.png
by solving this:

upload_2016-3-24_13-19-53.png


With
upload_2016-3-24_13-20-12.png
and
upload_2016-3-24_13-20-22.png
and
upload_2016-3-24_13-20-30.png


(where m is the rest mass).

The value you find for
upload_2016-3-24_13-22-0.png
, allows you for instance to determine from what speed you need to be considering relativistic effects based on the threshold you chose from the error in your experimental data.
 

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Physics-Tutor said:
HI Amy, Ray is correct. All depends on the error you are willing to consider

It might be relevant to neglect the Rel. effect or not depending on what you are trying to achieve.

For example, you can calculate the fraction of the speed of light for which you have to take into account relativistic effects, given a certain experimental framework.

You can set the threshold of difference you need. Say, I consider 1% as being the threshold above which I will consider relativistic effects for KE. I can calculate View attachment 97873 by solving this:

View attachment 97867

With
View attachment 97868 and View attachment 97869 and View attachment 97870

(where m is the rest mass).

The value you find for View attachment 97874 , allows you for instance to determine from what speed you need to be considering relativistic effects based on the threshold you chose from the error in your experimental data.

Physiscs-Tutor, hello
I see your point, thank you very much for explaining it to me:smile:
 
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Physics-Tutor said:
HI Amy, Ray is correct. All depends on the error you are willing to consider

It might be relevant to neglect the Rel. effect or not depending on what you are trying to achieve.

For example, you can calculate the fraction of the speed of light for which you have to take into account relativistic effects, given a certain experimental framework.

You can set the threshold of difference you need. Say, I consider 1% as being the threshold above which I will consider relativistic effects for KE. I can calculate View attachment 97873 by solving this:

View attachment 97867

With
View attachment 97868 and View attachment 97869 and View attachment 97870

(where m is the rest mass).

The value you find for View attachment 97874 , allows you for instance to determine from what speed you need to be considering relativistic effects based on the threshold you chose from the error in your experimental data.
You can use the LaTeX editor, you know. Just thought I'd tell you in case you didn't know, and was getting annoyed with attaching images :smile::smile:

##KE_{rel} =(\gamma-1)mc^2##
Code:
KE_{rel} =(\gamma-1)mc^2
 
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ProfuselyQuarky said:
You can use the LaTeX editor, you know. Just thought I'd tell you in case you didn't know, and was getting annoyed with attaching images :smile::smile:

KErel=(γ−1)mc2KErel=(γ−1)mc2KE_{rel} =(\gamma-1)mc^2

Thank you ProfuselyQuarky, I'll definitely check it out... :-) Could be a less painful than typing the equation in word, capturing pictures and posting them in my posts!
 
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Physics-Tutor said:
Thank you ProfuselyQuarky, I'll definitely check it out... :-) Could be a less painful than typing the equation in word, capturing pictures and posting them in my posts!
Totally! Give it a try! :-p
 
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