Massive Vector Boson E.o.M.: Minimize Action & Lorentz Gauge?

  • Thread starter Thread starter ChrisVer
  • Start date Start date
  • Tags Tags
    Boson Vector
ChrisVer
Science Advisor
Messages
3,372
Reaction score
465
Starting from the Lagrangian density:
L= -\frac{1}{4}F_{\mu\nu}F^{\mu\nu} + \frac{m^{2}}{2} B_{\mu}B^{\mu}
we can derive the E.o.M. for the field B which read:

( \partial^{2} + m^{2}) B^{\mu} - \partial^{\mu} (\partial B) = 0
In the case of a massive field, I am not sure how I can kill out the partial of B through the field equations...
\partial B=0
Does this come as a constraint/boundary condition of minimizing the action? or is there something I cannot see? In most cases they state it's a Lorentz Gauge, however I am not sure how this can be indeed shown...
 
Last edited:
Physics news on Phys.org
http://www.theory.nipne.ro/~poenaru/PROCA/proca_rila06.pdf
P.180 , eq 19,20 and the 1st paragraph of p.181 gave the answer... One has to take the derivative of the Equations of Motion \partial_{\mu} and \partial B comes out zero... (unfortunately for me I came out with the wrong EoM missing a minus sign and I couldn't even think of doing it)
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Back
Top