Massive Vector Boson E.o.M.: Minimize Action & Lorentz Gauge?

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ChrisVer
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Starting from the Lagrangian density:
L= -\frac{1}{4}F_{\mu\nu}F^{\mu\nu} + \frac{m^{2}}{2} B_{\mu}B^{\mu}
we can derive the E.o.M. for the field B which read:

( \partial^{2} + m^{2}) B^{\mu} - \partial^{\mu} (\partial B) = 0
In the case of a massive field, I am not sure how I can kill out the partial of B through the field equations...
\partial B=0
Does this come as a constraint/boundary condition of minimizing the action? or is there something I cannot see? In most cases they state it's a Lorentz Gauge, however I am not sure how this can be indeed shown...
 
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http://www.theory.nipne.ro/~poenaru/PROCA/proca_rila06.pdf
P.180 , eq 19,20 and the 1st paragraph of p.181 gave the answer... One has to take the derivative of the Equations of Motion \partial_{\mu} and \partial B comes out zero... (unfortunately for me I came out with the wrong EoM missing a minus sign and I couldn't even think of doing it)
 

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