Master Elastic Collision Problems: Basic Help | Homework Solution

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The discussion revolves around difficulties with elastic collision problems, specifically the conservation of linear momentum and kinetic energy. The user presents a scenario involving two particles, where one is initially at rest, and seeks to determine the final velocities after a collision. They recognize the need to use both momentum and kinetic energy equations to solve for the unknowns but express uncertainty about the correct approach. The user also reflects on their test performance, acknowledging a missed opportunity to apply these concepts. Ultimately, they find a formula for the final velocities but continue to seek clarity on their method.
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Homework Statement


Some days ago and specially yesterday I realized I have a strong weakness when it comes to elastic collision problems. Unfortunately I disregarded it and I couldn't finish an exercise in a test today.


Homework Equations


Linear momentum is conserved (\vec{P_{i}}=\vec{P_f}}) and so is the kinetic energy of the system. (Two bodies)


The Attempt at a Solution



Well in fact say you have 2 particles, m_1 and m_2. m_2 is initially at rest while m_1 has a speed of \frac{4m}{s}.
If m_1 hits m_2, what would be the speed of m_2?

I get that m_1v_1=m_1v_1'+m_2v_2' [1]. One equation, two unknowns: v_1' and v_2'.
Have I to work it out using the equation of the kinetic energy? \frac{m_1v_1^2}{2}=\frac{m_1v_1^2'}{2}+\frac{m_2v_2^2'}{2}. I solve for v_1' and back substitute it in [1]. Is it the way to find out v_1' and v_2'?
If yes then I thought about it during the test but I was too lazy to do it... (it doesn't count for my average but still, I should have done that).
Thanks for your confirmation or infirmation.
 
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Thank you very much iseidthat!
That doesn't answer my question I think, but at least I've learned that v_1'=\left( \frac{m_1-m_2}{m_1+m_2}\right) v_1 and that v_2' can be determinate by a given formula.
Ok, I'll try to answer my question by my own.
 
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