Mastering Identities: Solving Tricky Problems in Pre-Cal 2

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The discussion focuses on a Pre-Calculus 2 problem involving trigonometric identities, specifically how to manipulate fractions involving secant and tangent. The user expresses difficulty in selecting the correct identity and changing the denominator in the equation Sec/Tan - Tan/Sec = cosxcotx. A suggestion is made to think of the problem in terms of dividing fractions, which can simplify the process. The conversation emphasizes the importance of understanding arithmetic operations with fractions to solve the identity correctly. Overall, the thread highlights the challenges students face in mastering trigonometric identities in Pre-Calculus.
msdenise15
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Hi,

I'm new to this site and I'm very happy that I found it. My Pre-cal 2 teacher has been no help to me when it comes to explaining certain steps needed to solve a problem. Overall I'm having a hard time choosing the correct identity needed to solve the problems. However what I do not understand about this particular problem is how to change the denominator.

The question is:

Sec/Tan -Tan/Sec = cosxcotx

I started by expanding sec and tan which gave me (1/cos)/(sin/cos)-(cos/sin)/(1/cos)

but what should I do to change the denominator?
 
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That's a good start. Now think back to arithmetic: What do you do when you are asked to divide two fractions? I ask this, because that's exactly what you have there. For instance:

\frac{\frac{1}{\cos(x)}}{\frac{\sin(x)}{\cos(x)}}=\frac{1}{\cos(x)}\div\frac{\sin(x)}{\cos(x)}

Does that help?
 
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