Material Science- x-ray diffraction and metal densities

AI Thread Summary
The discussion focuses on calculating the density of a metal with a BCC crystal structure and an atomic weight of 92.91 using x-ray diffraction data. The angle of diffraction for the (211) planes is given as 41.148° with a wavelength of 0.14 nm. Key equations include the relationship between lattice parameter, atomic radius, and the density formula involving the number of atoms, atomic weight, and volume. The user is seeking guidance on determining the lattice parameter without having the atomic radius. The conversation emphasizes the need to convert angles to radians for accurate calculations.
maiad
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Homework Statement



Consider a metal with an BCC crystal structure and atomic weight 92.91. When monochromatic x-radiation having a wavelength of 0.14 nm is used, the angle of diffraction (2*theta) for the (211) set of planes in this metal occurs at 41.148 ° (first-order reflection).


Compute the density of this metal in g/cm^3


The sin function requires input in radians.


Use decimal notation, digits after decimal: 2

Homework Equations



a=4R/sqrt(3)

p=n*A/V*N

n*lamba=2d(hkl)sin(theta)

d(hkl)=a/sqrt(h^2 +k^2 + l^2)


The Attempt at a Solution



i basically broke down the equation into P=(2Asin(theta)) / ((a^2)(sqrt(h^2+k^2+l^2))

but for the vaule of a... i don't have the radius to find the vaule of a soo any hints would be nice :)
 
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maiad said:
n*lamba=2d(hkl)sin(theta)

What is known, what is unknown?
 
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