Materials and their use in structures

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To determine the strain per unit volume in the cable when a stress of 6.4 x 10^(8) Pa is applied, one must first calculate the strain, which is the change in length divided by the original length. The cable stretches by 1.2 x 10^(-4)m from its original length of 12.0m, resulting in a strain of 1.0 x 10^(-5). The energy per unit volume, or strain energy density, can be found using the area under the stress-strain curve, which is represented as 0.5 times stress times strain. Therefore, the strain energy density in the cable is 3.2 J/m^3 when this stress is applied.
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A cable has an unstretched length of 12.0m and is stretched by 1.2 x 10^(-4)m when a 6.4 x 10^(8) Pa stress is applied. What is the strain per unit volume in the cable in J m^(-3), when this stress is applied?

Any help would be very nice. I don't understand what to do.
 
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When a graph of stress vs. strain is drawn, up to the yield point (or around there), it is a straight line in the elastic region.

It forms a triangle. So the area under that graph gives the energy.
 

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