- #26

- 533

- 150

Going from ##\lim_{y\to 0} \frac{y}{\sqrt{\sin^2{y/2}}}## to ##\lim_{y \to 0} \frac{y}{\sin{y/2}}## was wrong since approaching ##0## from the left is different from approaching it from the right when it comes to the sine function. Remember that ##\sqrt{u^2}=|u|##.Can you please explain a little more about which part you’re talking about?

You also made an error when you applied this ##\sin^2{(x/2)}=\frac{1-\cos x}{2}##.

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