fluidistic
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Homework Statement
For what values of K does the DE xy''-2xy'+(K-3x)y=0 (1) has a bounded solution in (0, \infty)?
Homework Equations
Not so sure, Frobenius method maybe.
The Attempt at a Solution
First, I check what happens when x tends to infinity. I see that the DE behaves like \phi ''-2 \phi '-3 \phi =0. Where \phi (x)=c_1e^{3x}+c_2e^{-x}. I checked out and this indeed satisfies the DE (2).
I propose a solution to (1) of the form y(x)=f(x) \phi (x). So I calculated y' and y'' and replaced all this into the DE (1) and after a lot of algebra I reached that the DE (1) is equivalent to the DE f''(x)+4f'(x)+f(x) \left ( \frac{Kc_1e^{3x}}{x} \right ) \cdot \left ( \frac{1}{c_1e^{3x}+c_2e^{-x}} \right )=0 (3) where these c_1 and c_2 differs from the ones given in the expression for \phi (x) but this doesn't matter, they are constants. Now I must say I'm not really eager to use Frobenius's method on the DE (3). Mainly due to the denominator. I don't really know how to proceed... any help will be appreciated as usual.