How much energy is released in a matter-antimatter annihilation event?

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Matter-antimatter annihilation events release energy equivalent to the mass of the particles involved, as described by Einstein's equation E=mc². A single annihilation of a proton and an antiproton can yield energy significantly greater than that of a hydrogen bomb. The discussion raises questions about the amount of energy needed for practical applications, such as calculating kilowatt-hours from these events. It highlights the potential of antimatter propulsion drives in science fiction as a feasible concept based on real physics. Understanding the mass of protons and antiprotons, which is approximately 938.3 MeV/c², is essential for these calculations.
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Science-fiction movies and TV shows often refer to antimatter propulsion
drives. This is not as far-fetched as it may seem. In a matter-antimatter
annihilation event, a particle and its antiparticle annihilate each other and
release all of their mass energy (such as in the reaction p+p→2γ, for
example). How many of these matter-antimatter annihilation events are
needed to get our kWh of energy? And what is the total mass of protons and
antiprotons required to do this?

Hint: The antiproton has the same mass as that of the proton,
938.3 MeV/c2 = 1.6726ï10-27 kg.

I'm not great with the whole concept of anti-matter, any help please? Such as equations to use and general concepts?
 
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Hi abohn1! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

You don't need to know anything about anti-matter (and it's the same as matter, anyway :wink:) …

just use e = mc2. :smile:
 
actually antimatter-matter collisions create so much power! one particle of antimatter with one particle of matter will create 200 times the energy of a hydrogen bomb!
 
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