Max Height of Rolling Ball & Kinetic Energy Calculation

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To determine the maximum height a hollow ball reaches on an incline after rolling at 3.4 m/s, all its kinetic energy converts to potential energy at the peak. The height can be calculated using the formula for gravitational potential energy. For the solid sphere weighing 2.4 kg and rolling at 6.6 m/s, its translational kinetic energy can be found using the formula KE_trans = 0.5 * m * v^2, while the rotational kinetic energy requires the moment of inertia and angular velocity. The rotational kinetic energy for a solid sphere can be derived from its rolling motion, considering the radius and speed of a point on its circumference. Understanding these principles is crucial for solving both problems effectively.
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two question important !

1) A hollow ball is rolling along a horizontal surface at 3.4 m/s when it encounters an upward incline. If it rolls without slipping up the incline, what maximum height will it reach?
h= ...meter

2) A solid 2.4 kg sphere is rolling at 6.6 m/s . Find (a) its translational kinetic energy and (b) its rotational kinetic energy.


pleeeeeeeeeeeeease help me with that as soon as possible
 
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1, What is it's kinetic energy - if it stops at the top of the incline all this goes into potential energy what is the height.

2, You need the equation for rotational ke of a solid sphere (it's in wiki or your textbook)
Then since it is rolling you can get the radius from considering how fast a point on the circumference is moving along the plane.
 

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