Max Power Rating for 800:80 Transformer w/ 120V & 15A CB

  • Thread starter Thread starter tnkfub
  • Start date Start date
AI Thread Summary
The discussion centers on calculating the maximum power rating for an 800:80 transformer connected to a 120V outlet with a 15A circuit breaker. Participants emphasize the importance of understanding the turns ratio to determine the secondary voltage and clarify whether this is expressed in peak-to-peak or root mean square values. Additionally, the placement of the circuit breaker, typically in series with the primary winding, is highlighted for safety reasons. The conversation also prompts users to calculate the maximum current, voltage, and power based on the circuit breaker specifications. Overall, the thread seeks to guide users in applying electrical principles to solve the transformer power rating problem.
tnkfub
Messages
7
Reaction score
0
You are using a transformer with 800 loops in the primary and 80 loops in the secondary . if the transformer is plugged into a 120 v outlet and protected by 15 a cb what is the maximum power rating of an application that could be used ?
 
Physics news on Phys.org
Please show what you have done.
 
ranger said:
Please show what you have done.


The whole idea of me posting this is to get help ... ?
 
Well, then you have misunderstood what PF is about.
Did you read the guidelines?
We do NOT do your homework for you!
 
tnkfub said:
The whole idea of me posting this is to get help ... ?
So some of the work you could show us to get the ball rolling...

-- Given that turns ratio, what is the secondary voltage? Is it in Vpp or Vrms?

-- Is the fuse usually put in series with the primary or secondary winding? Why?

-- Given the fuse value (what's CB by the way?), what maximum current, voltage and power is possible?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top