- #1
erisedk
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Homework Statement
Two bodies of masses 1 kg and 4 kg are connected to a vertical spring, as shown in the figure. The smaller mass executes simple harmonic motion of angular frequency 25 rad/s, and amplitude 1.6 cm while the bigger mass remains stationary on the ground. The maximum force exerted by the system on the floor is (take g=10ms−2)
Homework Equations
The Attempt at a Solution
ω = √k/m
So, k = mω2 = 1×252 = 625
The maximum force will be exerted on the floor when the 1kg mass is at the lowest position, as the spring will be highly compressed and will push the bottom block.
So, total force on ground = 4g + kA + 1g
= 40 + 625*1.6*10-2 + 10
= 60 N
Now, someone asked me why I was adding the weight of the upper block ie. 1g as it isn't directly interacting with the 4 kg block. Only the spring force (and weight of 4kg block) are acting on the 4kg block, so the normal reaction should only depend on the two but not on the upper block. I don't know how to justify this even though I intuitively feel that the weight of the 1kg block should be added as it is part of the system. Can somebody provide a more rigorous explanation?