Maximum Acceleration for Crate on Moving Flatbed

  • Thread starter Thread starter landerson888
  • Start date Start date
AI Thread Summary
To determine the maximum acceleration of a flatbed truck carrying a 20KG crate on a 15-degree incline with a static friction coefficient of 0.400, it's essential to analyze the forces acting on the crate. The gravitational force acting down the slope and the frictional force opposing this motion must be considered. The net force can be expressed as F = ma, where 'a' is the acceleration of the truck. Calculating the forces will reveal the maximum acceleration the truck can achieve without the crate sliding. Understanding these dynamics is crucial for ensuring the crate remains stationary during transport.
landerson888
Messages
2
Reaction score
0

Homework Statement



a flatbed truck is carrying a 20KG crate down a sloping road inclined 15 degrees above the horizontal. The coefficient of static friction between the crate and the bed in 0.400. what is the maximum acceleration that a truck can have if th4 crate is to stay in place?

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
the crate stays still on a moving flatbed truck
 
What is the acceleration of the crate with respect to the ground?
If there is acceleration, there is a net force of F=ma. What forces act on the crate?

ehild
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top