Maximum Current in AC Circuit Problem

AI Thread Summary
The problem involves a 200Ω resistor connected to an AC generator with a peak voltage of 10.0V, asking for the peak current at frequencies of 100Hz and 100kHz. The relevant equation used is V=IR, leading to a calculated peak current (Imax) of 0.05A for both frequencies. Participants confirm that the frequency does not affect the current in this specific scenario, making the question appear simpler than expected. The discussion emphasizes the straightforward nature of the calculation despite initial concerns about the frequency's relevance. Overall, the solution is validated as correct.
Sandbox.WeC
Messages
5
Reaction score
0

Homework Statement


A 200? resistor is connected in series with an AC generator that produces a peak voltage of 10.0V. What is the peak current through the resistor if the frequency of the source is (a) 100Hz and (b) 100kHz


Homework Equations


V=IR


The Attempt at a Solution


I just plugged in the numbers and I arrive at a value of Imax=0.05A for both part a and part b. Is this correct? I am just uncertain if the question is only trying to lead me astray with the frequency values as they do not seem to play a part in this solution.
 
Last edited:
Physics news on Phys.org
Hi Sandbox.WeC, welcome to Physics Forums.

You are correct.
 
Thanks a lot. This question just seemed... Overly simple.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Combined tensions of an RLC series circuit with AC current
Replies
3
Views
835
Calculation of current in driven series RLC circuit
Replies
8
Views
2K
Verifying Kirchoff's law in an AC RLC circuit
Replies
7
Views
2K
AC circuit, voltage and frequency problem
Replies
10
Views
2K
Why don't voltages add up numerically in an LCR AC circuit?
Replies
5
Views
3K
AC supply - Signal generator - CRO in circuits
Replies
9
Views
2K
Finding displacement current in an AC capacitor circuit
Replies
7
Views
4K
The voltage across an AC source and a resistance in series
Replies
4
Views
2K
How to Determine Values of L and C in a Series RLC Circuit at Resonance?
Replies
8
Views
2K
Maximum Energy Stored in a Capacitor in an AC circuit
Replies
6
Views
9K

Hot Threads

Recent Insights

Back
Top