Maximum Height of Projectile Using Cons. of Energy

AI Thread Summary
To find the maximum height of a projectile launched at 45 m/s and 56° using conservation of energy, the vertical component of the initial velocity must be calculated. The relevant equations include potential energy (PE) and kinetic energy (KE), specifically mgh = 1/2 mv^2. The angle affects the vertical velocity, which is crucial for determining height. The correct approach involves using the vertical component in the formula h = (v_y^2)/(2g), where v_y is the initial vertical velocity. Understanding the significance of the launch angle is essential for solving the problem accurately.
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Homework Statement



A projectile is launched with a speed of 45 m/s at an angle of 56° above the horizontal. Use conservation of energy to find the maximum height reached by the projectile during its flight.


Homework Equations


PE=KE
mgh=1/2mv^2
gh=1/2v^2
h=.5v^2/g


The Attempt at a Solution


I thought in this equation that the angle wouldn't matter, but I know I'm wrong. I thought you could just plug it the numbers to the manipulated formula h=.5v^2/g. Please help! thanks
 
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Yes the angle matters. You need to consider the vertical component of the initial velocity.
 

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