Maximum speed of a car on the bridge

AI Thread Summary
The maximum speed of a car on a bridge with a circular arc of radius 300 m is determined by the balance between centripetal force and gravitational force. When the normal force is zero, the car will lose contact with the surface. This occurs when the centripetal acceleration equals gravitational acceleration. To find the maximum speed, the equation v²/r = g can be used, where v is the speed, r is the radius, and g is the acceleration due to gravity. Understanding these forces is crucial for solving the problem effectively.
wal33d
Messages
1
Reaction score
0
the vertical cross section of a bridge is a circular arc of radius 300 m. what is the maximum speed at which the car will not leave the surface while passing at the top of the bridge?

i just can't seem to understand where to go with this problem
help please!
 
Physics news on Phys.org


Hi wal33d, welcome to PF.
When the normal reaction from the ground is greater than the weight of the car, it will leave the ground. In the curved surface, the normal reaction is due to the centripetal force.
 


rl.bhat said:
Hi wal33d, welcome to PF.
When the normal reaction from the ground is greater than the weight of the car, it will leave the ground. In the curved surface, the normal reaction is due to the centripetal force.

When the car leaves the ground, the normal force is 0. The normal force is 0 when the centripetal acceleration of the car is equal to the acceleration of gravity.
 


Yes.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top