Maximum speed of a cylinder dropped on a spring

AI Thread Summary
The discussion focuses on calculating the maximum speed of a cylinder dropped onto a spring, with specific parameters provided. The user confirmed their calculations for maximum spring compression and spring deflection but questioned their result for maximum velocity, which was lower than the expected value. They attempted to equate gravitational potential energy with kinetic energy to find the velocity but expressed confusion about when the speed is at its maximum. Responses suggest clarifying the calculations and considering the dynamics of the cylinder's motion just after impact. The conversation emphasizes the importance of understanding energy conservation in this context.
Rajveer97
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Homework Statement


Cylinder A (mass = 5kg) is released from rest at a height h =100mm above a spring of stiffness k = 1.8 kN/m. Determine, (i) the maximum compression of the spring, (ii) the spring deflection when the cylinder’s velocity is a maximum, and, (iii) the maximum velocity of the cylinder

I just need to confirm part iii

Homework Equations


Ep=mgh
Ek=(1/2)mv^2
Es=(1/2)kx^2
F=kx

The Attempt at a Solution


For part (i) I got 0.106
(ii) 27.2mm
For (iii) I did Ep=Ek which gave me v=1.4. The correct answer is supposed to be 1.49, I feel my answer is similar is wrong but similar just by chance. I just don't fully understand the question, when will the speed be maximum, before or after deflection? I feel before but I'm unsure.

Thanks
 
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Hi,
You don't really specify what you did. Could there be a term missing in your 'doing'?
 
BvU said:
Hi,
You don't really specify what you did. Could there be a term missing in your 'doing'?
Well I meant I basically made gravitational potential energy equal kinetic energy and solved for v
 
Es ?
 
Rajveer97 said:
I did Ep=Ek
What, roughly, is the cylinder's acceleration very shortly after hitting the spring?
 
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