Max Temp in Ideal Gas Transformation: 2490K

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The discussion revolves around calculating the maximum temperature of an ideal gas undergoing a transformation defined by the equation p = p_0 - aV, with given constants. Participants note that the ideal gas law, pV/T = constant, can be used to derive temperature as a function of volume. It is suggested that substituting the pressure equation into the ideal gas law will help find the maximum temperature. However, there is uncertainty about whether the number of moles of gas is necessary for a definitive numerical answer. The maximum temperature options provided include values ranging from 2450 K to 2500 K, with 2490 K being a focal point.
KingAntikrist
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Again, it's a translation, i don't know if it's 100% accurate in english

Homework Statement



An ideal gas suffers a transformation under the law p=p_0-aV, p_0=10^5 Pa, a=\frac{10^6}{8,3} \frac{Pa}{m^3}. The maximum temperature on this transformation is: ...

A) 2450 K
B) 2500 K
C) can't be calculated (THIS IS NOT THE ANSWER)
D) 2480 K
E) 2490 K
F) 2460 K

Homework Equations



\frac{pV}{T}= ct

The Attempt at a Solution



The attempt? Nill...not even my physics teacher could solve this (private lesson with him). And i really don't have any ideea...

That aV is actually another pressure...
 
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Substitute p(V) from the equation to the ideal gas equation to obtain T(V). For V>0, find max(T) :smile:

EDIT: I think the number of moles of the gas must be given for a numerical value of Tmax.
 
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