Maximum value of E = a.sin(x) + b.cos(x)

  • Thread starter Thread starter JOEandSTEPH
  • Start date Start date
  • Tags Tags
    Maximum Value
JOEandSTEPH
Messages
5
Reaction score
0
We've been given the following equation,

E = 15.sin(50.pi.t) + 40.cos(50.pi.t)

We've been asked to find a value of E we think at its maximum value (can't quite remember the question at the moment). We know that the second derivative will give us whether the equation gives the maximum or minimum value (think it's giving us the maximum anyway) so we're sure that we are just required to differentiate it once, equal it to zero to find a value for t and then put the value of t back into the original equation.

dE/dt = 750.pi.cos(50.pi.t) - 2000.pi.sin(50.pi.t)

The problem is when we transpose the equation because we get really confused. This is as far as we've got:

750.pi.cos(50.pi.t) - 2000.pi.sin(50.pi.t) = 0
750.pi.cos(50.pi.t) = 2000.pi.sin(50.pi.t)
cos(50.pi.t) = [2000.pi.sin(50.pi.t)] / 750.pi
50.pi.t = cos-1([2000.pi.sin(50.pi.t)] / 750.pi)
t = [cos-1([2000.pi.sin(50.pi.t)] / 750.pi)] / 50.pi

Okay, so now what happens? There is still a t on the right side of the equation and we don't know how you can get it over to the other side to get t to the 2 and then square root the right side.

Any ideas? Are we way off? Any help would be greatly appreciated.

Thanks.
 
Physics news on Phys.org
You don't want to take cos-1. Divide both sides of your equation by cos(50.pi.t) and remember sin/cos=tan.
 
Okay I think I get what you're saying.

So,

750.pi.cos(50.pi.t) - 2000.pi.sin(50.pi.t) = 0
750.pi.cos(50.pi.t) = 2000.pi.sin(50.pi.t)
750.pi = 2000.pi [sin(50.pi.t)] / cos(50.pi.t)]
750.pi = 2000.pi.tan(50.pi.t)
750.pi / 2000.pi = tan(50.pi.t)
tan-1[750.pi / 2000.pi] = 50.pi.t

t = (tan-1[750.pi / 2000.pi] / 50.pi
 
JOEandSTEPH said:
Okay I think I get what you're saying.

So,

750.pi.cos(50.pi.t) - 2000.pi.sin(50.pi.t) = 0
750.pi.cos(50.pi.t) = 2000.pi.sin(50.pi.t)
750.pi = 2000.pi [sin(50.pi.t)] / cos(50.pi.t)]
750.pi = 2000.pi.tan(50.pi.t)
750.pi / 2000.pi = tan(50.pi.t)
tan-1[750.pi / 2000.pi] = 50.pi.t

t = (tan-1[750.pi / 2000.pi] / 50.pi

Yes. That's the right way to solve an equation like that for t.
 
That gives us t = 2.284 milliseconds

So E = 15.sin(50.pi.[2.284x10-3]) + 40.cos(50.pi.[2.284x10-3])

So E = 42.72
 
Thank you, Dick!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top