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Maximum Vertical Distance

  1. Feb 7, 2008 #1
    1. [​IMG]

    I get (a) part but for the last part to find the vertical distances can someone explain what is done here. This is the solution

    let h be the vertical distance

    h = y + xtan30

    h= vot tan30 - 1/2gt^2

    then they differentiate to find maximum (i get that part). I just dont understand how they came up with those equations for the h distance...

    can anyone explain?
    Last edited: Feb 7, 2008
  2. jcsd
  3. Feb 7, 2008 #2


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    Homework Helper

    One of the equations of motion s = ut + 1/2at^2
    Where s is distance, u is initial velocity, a is accelaration.
    If you only think about the vertical motion of the skier, what is the initial vertical velocity and what is the accelaration.
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