Maxwell Lagrangian at weak fields

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SUMMARY

The discussion centers on the conditions under which the constant of integration, C, in the equation from the paper "http://arxiv.org/abs/hep-th/9506035" must vanish to align with the standard Maxwell Lagrangian at weak fields. The equation presented is $$\frac{1}{4}\eta^{\mu\nu\lambda\rho} F_{\mu\nu}F_{\lambda\rho} = \eta_{\sigma\tau\alpha\beta}\frac{\partial L}{\partial F_{\sigma\tau}} \frac{\partial L}{\partial F_{\alpha\beta} } + 2C$$. The necessity for C to equal zero arises from the requirement that the Lagrangian must yield consistent results when no field is present, reinforcing the foundational principles of electromagnetism.

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  • Understanding of the Maxwell Lagrangian
  • Familiarity with tensor notation and indices
  • Knowledge of classical field theory
  • Basic concepts of weak field approximations
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  • Study the derivation of the Maxwell Lagrangian in classical electrodynamics
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The discussion is beneficial for theoretical physicists, graduate students in physics, and researchers focusing on classical field theories and electromagnetism.

PhyAmateur
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In http://arxiv.org/abs/hep-th/9506035 the author said after writing this equation:

$$\frac{1}{4}\eta^{\mu\nu\lambda\rho} F_{\mu\nu}F_{\lambda\rho} = \eta_{\sigma\tau\alpha\beta}\frac{\partial L}{\partial F_{\sigma\tau}} \frac{\partial L}{\partial F_{\alpha\beta} } + 2C$$

where C was arbitrary constant of integration." In fact, if L is to agree with the usual Maxwell Lagrangian at weak fields the constant must vanish". Why? I mean why should the constant vanish. It seems that I don't understand what he meant by Maxwell Lagrangian at "weak fields".
 
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Imagine the case of no field at all. Everything apart from the constant is zero, so the constant has to be zero as well.
 

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