Measurement of Lx: Result of Measurement?

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Homework Help Overview

The discussion revolves around the measurement of the angular momentum operator \(L_x\) in quantum mechanics, specifically in the context of a wave function expressed as \(\psi = zf(r)\). Participants are exploring how to determine the result of measuring \(L_x\) and the implications of eigenvalue equations in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the wave function and the measurement of \(L_x\), noting the need for eigenvalue equations to interpret measurement results. There are attempts to express \(L_x\) in terms of its components and to understand the expected value of the measurement. Questions arise regarding how to derive the outcome of an individual measurement versus the expected value.

Discussion Status

The discussion is ongoing, with participants providing insights into the mathematical framework for measuring \(L_x\) and questioning how to interpret the results. Some guidance has been offered regarding the use of the differential form of the operator and the integration process for expected values, but there is no consensus on the specific outcome of an individual measurement.

Contextual Notes

Participants note that the wave function is dependent on variables \(r\) and \(\theta\), and there is a mention of the integration process required to compute expected values. The discussion highlights the complexity of quantum measurements and the potential for outcomes that may not align with expected values.

Physgeek64
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Homework Statement


If we have a wave function ##\psi =zf(r)## and we take a measurement of ##L_x## what is the result of the measurement?

Homework Equations

The Attempt at a Solution


So i know we can write ##L_x=\frac{1}{2}(L_+ + L_- )## and that ##|\psi > = g(r) |1,0> ## so ##L_x |\psi >= \frac{1}{2} \sqrt{2} g(r) |1,1>##. But i don't know what the measurement would be because this has to be an eigenvalue equation to read off the result of a measurement (I think?).

Many thanks!
 
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Physgeek64 said:

The Attempt at a Solution


So i know we can write Lx=12(L++L−)Lx=12(L++L−)L_x=\frac{1}{2}(L_+ + L_- ) and that |ψ>=g(r)|1,0>|ψ>=g(r)|1,0>|\psi > = g(r) |1,0> so Lx|ψ>=12√2g(r)|1,1>Lx|ψ>=122g(r)|1,1>L_x |\psi >= \frac{1}{2} \sqrt{2} g(r) |1,1>. But i don't know what the measurement would be because this has to be an eigenvalue equation to read off the result of a measurement (I think?).

Many thanks!

you have a given wave function which is a function of r and theta only
if you wish to find expected value of L(x) then one must use differential form of the operator L(x)
 
drvrm said:
you have a given wave function which is a function of r and theta only
if you wish to find expected value of L(x) then one must use differential form of the operator L(x)
But how do i find the result of a measurement. I can show that the expected value is zero, but i don't know what the outcome of an individual measurement would be.
 
Physgeek64 said:
But how do i find the result of a measurement. I can show that the expected value is zero, but i don't know what the outcome of an individual measurement would be.

In QM the measurement is defined with the help of wave function
say you have a position wavefunction then you can measure x-operator

as {Psi * (x )Psi }integrated over the whole space.
similarly L(x) is a operator which is represented in (r,theta, phi) space .

put the complex conjugate of the wave function on the left and psi on the right and L(x) in between and integrate over whole space .
the result will give you measurement and it may not be zero.
 

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