Measuring the Richter Scale with logarithms

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An earthquake measuring 6.1 on the Richter Scale has a specific intensity that can be calculated using the formula I = I0 × 10^M. To find the magnitude of an earthquake that is twice as powerful, the intensity of the first earthquake (I1) must be determined, followed by calculating the new intensity (I2) as double that of I1. A key issue arises with the initial intensity reference (I0), which cannot be zero, leading to confusion about how to proceed with calculations. Clarification is needed on whether I0 should be set to 1, as the original text implies I0 represents an earthquake of intensity 0. The discussion highlights the need for a clearer understanding of the definitions and formulas used in Richter scale calculations, particularly regarding intensity and amplitude.
Gregory.gags
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An Earthquake measures 6.1 on the Richter Scale. What is the rating on an earthquake that is twice as powerful?

I = I0 × 10M
I-intensity of earthquake
I0-earthquake with intensity of 0
M-magnitude of earthquake on the Richter Scale

So I figured I'd use I1 = I0 × 106.1 to find the intensity of earthquake 1 (I1)
then, 2I=I2 to find the intensity of earthquake 2 (I2), which is double that of I1
and finally, M=log(I2/I0) to find the resulting magnitude, or rating, of the Richter Scale.

But my problem begins at the very beginning.

If I0 = 0 then I1 = 0 too...
and I'm quite thrown off by this.
Am I taking the totally wrong approach to this?
 
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Gregory.gags said:
An Earthquake measures 6.1 on the Richter Scale. What is the rating on an earthquake that is twice as powerful?

I = I0 × 10M
I-intensity of earthquake
I0-earthquake with intensity of 0
M-magnitude of earthquake on the Richter Scale

So I figured I'd use I1 = I0 × 106.1 to find the intensity of earthquake 1 (I1)
then, 2I=I2 to find the intensity of earthquake 2 (I2), which is double that of I1
and finally, M=log(I2/I0) to find the resulting magnitude, or rating, of the Richter Scale.

But my problem begins at the very beginning.

If I0 = 0 then I1 = 0 too...
and I'm quite thrown off by this.
Am I taking the totally wrong approach to this?

I0 can't be 0.
 
I know! :P I don't understand what else it could be though?? No additional info was given in the question and no one else that I have showed this to has a clue of what to do!
 
exactly! that would make sense wouldn't it? But no where in the question, or even in the lesson as a matter of fact, did it mention Io being equal to 1.
Quote from the text : "The Richter scale... is based on a comparison of intensities to Io, which is an earthquake of intensity 0."
Did I just understand that incorrectly?
 
Gregory.gags said:
exactly! that would make sense wouldn't it? But no where in the question, or even in the lesson as a matter of fact, did it mention Io being equal to 1.
Quote from the text : "The Richter scale... is based on a comparison of intensities to Io, which is an earthquake of intensity 0."
Did I just understand that incorrectly?
I don't think it was worded very well. In any case, the definition your book uses in terms of intensities seems unusual. I did a search yesterday when you posted your other question - most of the definitions I saw for Richter calculations involve the shaking amplitude, not the earthquake intensity.

The formula I saw gives the earthquake magnitude as ML = log10(A/A0(δ)), where A is the shaking amplitude of a given earthquake, and A0(δ) is a function of the distance from the epicenter of the quake.
 
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