Measuring Voltage with Distance in an Electric Circuit Lab

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SUMMARY

This discussion focuses on measuring voltage changes in relation to the distance of a lamp from a solar panel using a multimeter. Participants conclude that the inverse square law of light is a critical principle affecting the voltage readings, as it describes how light intensity diminishes with distance. The relationship can be modeled mathematically as V ∝ 1/r², where V is voltage and r is the distance from the light source. Understanding this relationship is essential for accurately interpreting the results of the lab experiment.

PREREQUISITES
  • Basic understanding of electric circuits and voltage measurement
  • Familiarity with the inverse square law of light
  • Knowledge of using a multimeter for voltage measurement
  • Concepts of light diffraction and refraction
NEXT STEPS
  • Study the inverse square law of light in detail
  • Learn how to use a multimeter effectively for various measurements
  • Research the relationship between light intensity and distance
  • Explore the effects of solar panel positioning on energy efficiency
USEFUL FOR

Students in physics or electrical engineering, educators teaching electricity concepts, and anyone conducting experiments related to solar energy and light intensity.

cgi093
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I'm conducting a lab in which I change the distance of a lamp from a solar panel and use a multimeter to measure the resulting voltage. What type of relationship am I supposed to find? My results seem to indicate either a relationship with either a quadratic equation as its model or an inverse power equation as its model. Could someone tell me what would make sense here? My class is learning about electricity and circuits, but we haven't yet covered how the concentration of light is dispersed over distance, how that would affect the energy received by a solar panel, etc. Thanks!
 
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Anyone know how this would work?
 


No, but I naturally would think that the inverse square law of light comes into play somewhere.
 


Thanks, but since we haven't gone into any more detail with light than diffraction and refraction and stuff like that, I can't really use that too much. Thanks for the input though.

Anyone else?
 


cgi093 said:
Thanks, but since we haven't gone into any more detail with light than diffraction and refraction and stuff like that, I can't really use that too much. Thanks for the input though.

Anyone else?

Well maybe you should learn. The inverse square law for light is a very fundamental one and certainly plays into your problem. I personally think it is the only thing that plays into your problem along with how the voltage changes with respect to how much power the panel is receiving. http://hyperphysics.phy-astr.gsu.edu/hbase/vision/isql.html.
 


Well I would guess that you would see the voltage across the panel drop as basically something like


V \propto \frac{1}{r^2}

Think about the radiation from one really tiny amount of time let out from your light bulb. It will leave and propagate in all different directions equally creating a spherical shell of radiation. At further distances away from the bulb this spherical shell will be large and have a large surface area. However the same amount of energy will be stored in the light in that area. Because the surface area of a sphere is 4\pi r^2 our power will get spread out as one over this or \propto 1/r^2.

Here is the wikipedia article on the basic principle behind this, it shows up everywhere. and the picure is a good demonstration of what i was saying to visualize.

http://en.wikipedia.org/wiki/Inverse-square_law
 


Okay thanks a lot guys. I think this will definitely get me started.
 

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