Mech energy and perplexing waterslide

  • Thread starter Thread starter sanstereo
  • Start date Start date
  • Tags Tags
    Energy
AI Thread Summary
The discussion revolves around two physics problems related to mechanical energy and power. The first problem involves calculating the speed of a runner who dissipates 0.6 J of mechanical energy per kg per step, given a power output of 70 W. The second problem concerns a child sliding down a frictionless waterslide from a height, requiring the calculation of the distance she lands from the base of the slide. Clarifications are sought regarding the energy dissipation per step for the runner and the configuration of the waterslide. The conversation emphasizes understanding energy dissipation in relation to speed and trajectory calculations.
sanstereo
Messages
2
Reaction score
0
hello, glad this site exisits.

i got a test coming up on work, power, k and p energy, so forth . . .

i got two test problems here that i can't figure out for the life of me.

a) While running a person dissapates .6 j of mechanical energy per kg of body mass. if a 60 kg runner dissapates a power of 70 W during a race, how fast is the person running? Assume a running step is 1.5 m long.

b) A child slides without friction from a height of h along a cuved waterslide. She is launched from a height of h/5 into the pool.
it looks as though the angle is 45 degrees in the slide and i need to find the distance or the x value when she lands in the pool.

if anyone can help me out here or if you need further info, drop a line. thanks a lot in advance . . .

peace . . .
 
Physics news on Phys.org
Does a) say 'per kg of body mass per step', by any chance?
 
yeah, sorry. it does say that, so add that to the problem. heh.
 
So if a person dissipates 0.6 J per kg per step, how much total energy does a person weighing 60 kg dissipate per step? Then, how much total energy does the runner dissipate per meter? How does this compare to 70 W? 70 W means 70 J are being dissipated each second - so, if a person dissipated 140 J per meter, that would mean it took a person two seconds to run a meter. You can get the speed from this.

In part b) - does the slide level off at the botom or does it end at an angle?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top