Mechanical - Deflection and Slope, cantilever beam

AI Thread Summary
The discussion focuses on calculating the deflection and slope at the free end of a cantilever beam subjected to both a point load and a uniformly distributed load (UDL). The user has computed the deflections and slopes for both loads but is uncertain whether to combine them. It is clarified that, due to the principle of superposition for small deflections, both deflections and slopes can be added together. The calculations provided include specific formulas for deflection and slope based on the loads and beam properties. The conversation emphasizes the importance of understanding beam basics to correctly apply these principles.
Sadlercomfrot
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Hi guys, I have been a question to solve this week to do with deflections and slopes at the free end of a cantilever beam. I have calculated the deflection and slope for the point load and UDL, but I'm not sure whether to add them together or not?.. as they're both acting on the beam?

A cantilever beam with a length of 7meters, has a 2KN point load at the free end and a UDL of 3KN/m along its length. Calculate the deflection and slope at the free end. *Assume the flexural stiffness [EI]is 800MPa.


This is what I've calculated so far, some steps have been omitted:

For the point load
dy/dx = (FL^2) / 2EI

dy/dx = 61.25x10^-6


y = (FL^3) / 3EI
y = 285.83μm

For the udl:
dy/dx = (wL^3) / 6EI

dy/dx =214.4x10^-6


y = (wL^4) / 8EI
y = 1.12mm

Now what? Do i add them?
Thanks,
 
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Yes. Beams are subject to superposition for small deflections.
 
Okay, what does that mean?

I add the deflections together? What about the slopes?
 
Last edited:
Sadlercomfrot said:
Okay, what does that mean?

I add the deflections together? What about the slopes?
If the deflections add, then the slopes, which are their derivatives, must add also.

Chet
 
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Nice source, thanks guys
 
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