Mechanics of materials-homework

AI Thread Summary
The discussion revolves around determining the maximum axial force P that can be applied to a thrust bearing without exceeding the allowable shear stress of 170 MPa. Participants clarify the confusion regarding the calculation of shear forces, emphasizing that the shear areas for the collar and thrust bearing are different and each must be considered individually. The correct approach involves applying the shear stress formula T = P/A separately for each surface area rather than summing the shear forces. Additionally, understanding the role of normal forces in maintaining equilibrium is highlighted as crucial for solving the problem. Overall, the conversation aims to clarify the mechanics behind the calculations necessary for the homework problem.
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Homework Statement



1–80. The thrust bearing consists of a circular collar A fixed to the shaft B.Determine the maximum axial force P that can be applied to the shaft so that it does not cause the shear stress along a cylindrical surface a or b to exceed an allowable shear stress of 170 MPa.

upload_2016-2-6_10-10-50.png
[/B]

Homework Equations



T=V/A or T = P/A[/B]

The Attempt at a Solution


This is how I thought I would draw my FBD

upload_2016-2-6_10-10-28.png


therefore I thought that if I did the summation of all forces in the x direction, P = Va+Vb
However, the solution takes it individually, like this:

T = P/A for a and T = P/A for b and calculates each P. This is confusnig me because, shouldn't the two V (shear forces) equal to the Maximum axial force?

thanks for any help, Id really like to understand this.
 

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I forgot to mention that for my FBD I did two cuts just so I can have a and b in there but I believed that we didnt need the rest.

I don't want any answers I just need some help with this, thank you!
 
Hellohi said:

Homework Statement



1–80. The thrust bearing consists of a circular collar A fixed to the shaft B.Determine the maximum axial force P that can be applied to the shaft so that it does not cause the shear stress along a cylindrical surface a or b to exceed an allowable shear stress of 170 MPa.

View attachment 95393[/B]

Homework Equations



T=V/A or T = P/A[/B]

The Attempt at a Solution


This is how I thought I would draw my FBD

View attachment 95392

therefore I thought that if I did the summation of all forces in the x direction, P = Va+Vb
However, the solution takes it individually, like this:

T = P/A for a and T = P/A for b and calculates each P. This is confusnig me because, shouldn't the two V (shear forces) equal to the Maximum axial force?

thanks for any help, Id really like to understand this.

If you draw a free body diagram of the shaft and the collar attached to it, how many forces will this diagram show? Which is the applied force and which is the reaction?
 
Do you mean just of the shaft and collar excluding the a and b surfaces?
 
Hellohi said:
Do you mean just of the shaft and collar excluding the a and b surfaces?
The collar is rigidly attached to the shaft, so you can't exclude it.

You have a thrust P applied to one end of the shaft. What keeps the shaft from accelerating in the direction opposite of P?
 
Oh! It should be the normal force correct?
 
the normal force that A exerts
 
Hellohi said:
the normal force that A exerts
Correct.

The shear area for the collar and the shear area for the thrust bearing are two different values. One of these surface areas will limit how large P can be, subject to the shear stress limit.
 
Thank you!
 
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