Solving Mechanics Questions: Cyclists A & B, Fly

  • Thread starter Raed
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In summary, cyclist A and B have initial displacements of 0 Km and 70 Km, respectively. They start cycling towards each other at velocities of 15 Km/hr and 20 Km/hr, respectively, while a fly starts flying towards B with a velocity of 30 Km/hr. When all three meet, the displacement of the cyclists and fly will be determined by the equations d1 = v1*t and d2 = v2*t, with the distances measured from A and B respectively. The distance traveled by the fly can be found by adding d1 and d2 when they meet.
  • #1
Raed
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Homework Statement



Two cyclists, A and B, have displacements 0 Km and 70 Km, respectively. At t = 0 they begin to cycle towards each other with velocities 15 Km/hr and 20 Km/hr, respectively. At the same time, a fly that was sitting on A starts flying towards B with a velocity of 30 Km/hr. As soon as the fly reaches B it immediately turns around and flies towards A, and so on until A and B meet.

a) What will the displacement of the two cyclists and the fly be when all three meet?

b) What will be the distance traveled by the fly?


Homework Equations



x = ut + 0.5at^2
v^2 = u^2 + 2as
v= at+u

The Attempt at a Solution



attempted a method of graphing but failed and attempted fill in variables in equations but failed again
 
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  • #2
There is no acceleration in this problem. The two cyclists move with constant velocities.
Try to find out when will they meet. The equations of motions are just
d1=v1*t
d2=v2*t
with the distances measured from A and B respectively.
What is d1+d2 when they meet?
 
  • #3


I would approach this problem by first identifying the key information and variables involved. From the given information, we can determine that cyclist A has a displacement of 0 Km, cyclist B has a displacement of 70 Km, and both are traveling towards each other with velocities of 15 Km/hr and 20 Km/hr, respectively. The fly starts at A and travels towards B with a velocity of 30 Km/hr.

Next, I would use the equations of motion to solve for the time it takes for the cyclists to meet. Using the equation x = ut + 0.5at^2, we can set the initial displacement of A to 0 Km and the displacement of B to 70 Km, and solve for t. This gives us a time of 5 hours for the cyclists to meet.

To determine the displacement of the fly when all three meet, we can use the equation x = ut + 0.5at^2 again, but this time with an initial velocity of 30 Km/hr and a time of 5 hours. This gives us a displacement of 150 Km for the fly when all three meet.

For part b, we can use the equation v = at + u to find the distance traveled by the fly. Since the fly starts at A with a velocity of 30 Km/hr and travels for 5 hours, the distance traveled by the fly would be 150 Km.

In conclusion, when all three meet, the displacement of the cyclists will be 35 Km each (since they have traveled 35 Km towards each other) and the displacement of the fly will be 150 Km. The total distance traveled by the fly would be 150 Km.
 

What are the equations used to solve mechanics questions involving cyclists and a fly?

The equations used to solve mechanics questions involving cyclists and a fly are the equations of motion, which include distance (d), velocity (v), time (t), and acceleration (a). These equations are d = vt, v = u + at, and v^2 = u^2 + 2ad, where u is the initial velocity.

How do you calculate the distance traveled by the cyclists and the fly?

To calculate the distance traveled by the cyclists and the fly, you can use the formula d = vt, where d is the distance, v is the velocity, and t is the time. For example, if cyclist A is traveling at a velocity of 10 m/s and cyclist B is traveling at a velocity of 15 m/s, and the fly is traveling at a velocity of 5 m/s, and the time is 2 seconds, then the distance traveled by cyclist A is 20 meters, cyclist B is 30 meters, and the fly is 10 meters.

How do you determine the final velocity of the cyclists and the fly?

To determine the final velocity of the cyclists and the fly, you can use the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. If there is no acceleration, then the final velocity will be the same as the initial velocity. If there is acceleration, then the final velocity will be different from the initial velocity.

What is the difference between the average velocity and the instantaneous velocity of the cyclists and the fly?

The average velocity of the cyclists and the fly is the total distance traveled divided by the total time taken. This gives an overall picture of the velocity over the entire journey. On the other hand, instantaneous velocity is the velocity at a specific moment in time. It can be calculated by finding the slope of the tangent line on a position-time graph at a specific point.

How does the presence of the fly affect the motion of the cyclists?

The presence of the fly does not have a significant effect on the motion of the cyclists, unless the fly is significantly larger in size and creates a noticeable resistance. In most cases, the fly's motion can be ignored and the cyclists can be treated as if they are moving in a vacuum.

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