Melting Ice Exam Help: Get Verified Answers for Last Year's Questions - Sarah

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Sarah is seeking help with last year's exam questions, specifically verifying her answers related to melting ice and heat transfer. She presents her answers for four questions but expresses uncertainty about her calculations, particularly for the first question. Other participants provide feedback, confirming some of her answers and discussing the methodology behind calculating heat transfer using the formula q = mc(delta T). The conversation shifts to relativity, with advice to start a new thread for those questions, emphasizing the distinction between general inquiries and homework help. The discussion highlights collaborative problem-solving in physics and chemistry concepts.
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Hi all, i am currently studying for an exam, and so i am going over the questions in last years exam. Unfortunately we were not given the answers, so i am not sure whether i am getting the questions right.
If its not too much trouble, and someone has a bit of time to spare, could they verify the answers to some of the questions i put up?

Thanks
Sarah

my first question is this:
http://img338.imageshack.us/img338/6000/picture900gz.th.png
my answers are:
(a) 0.063kg of ice melt
(b) 4 moles
(c) 14940 J
(d) 83.1 J/K
 
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Chemistry is not my thing. I get a different answer for the first one but I don't know if my method is right. Perhaps you see something in it though.

I figured that 0.5kg of 600K lead has 38.4kJ of heat. The freezing of the lead removes 12.4kJ or so, which leaves 26kJ. Melting ice requires 334.5kJ/kg, so that gives me 0.078kg. Take from it what you will.
 
vertigo said:
Chemistry is not my thing. I get a different answer for the first one but I don't know if my method is right. Perhaps you see something in it though.
I figured that 0.5kg of 600K lead has 38.4kJ of heat. The freezing of the lead removes 12.4kJ or so, which leaves 26kJ. Melting ice requires 334.5kJ/kg, so that gives me 0.078kg. Take from it what you will.
this isn't meant to be chemistry, lol, it is a physics course, though i spose this is a very 'chemistry' part of it.

yeah i think my answer for (a) might be wrong.

how did you come up with :
"I figured that 0.5kg of 600K lead has 38.4kJ of heat"

i guess you did it by using q = mc(delta T)

where delta T = 600 K

so we use absolute zero then, hmm interesting! :)

your method makes a lot of sense :D
 
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(a) I get 99 g
(b) correct
(c) righto
(d) yes.
 
Chi Meson said:
(a) I get 99 g
(b) correct
(c) righto
(d) yes.


cool, how did you get your 99g?


oh and how are you guys on relativity? :P
 
Look at the units of 0.128 kJ/(kg.K), to get kJ out of that you multiply by kg and K. 0.5kg * 600K * 0.128 = ?
 
vertigo said:
Look at the units of 0.128 kJ/(kg.K), to get kJ out of that you multiply by kg and K. 0.5kg * 600K * 0.128 = ?

ok, yep i see that , cheers :)
 
would it be cool if i asked some relativity questions aswell?
 
Sure, but start a new thread. If it is just a general question on SR, you should ask it in the SR forum. IF it is homework help you need, then ask it here.

edit: P.S. Special relativity and General Relativity is a sub-forum under "Astronomy and Cosmology"
 
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k. thanks :)
 
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