Mercedes-Benz on a hill (friction, normal force) Please help

AI Thread Summary
The discussion revolves around calculating the normal force and static frictional force for a Mercedes-Benz 300SL parked on a 20° incline. The weight of the car is determined by multiplying its mass (1700 kg) by the acceleration due to gravity (9.8 m/s²), resulting in 16660 N. The normal force is calculated using the formula FN = Wcos(θ), yielding approximately 15655.27 N. The static frictional force is found using Wsin(θ), resulting in about 5698.05 N. The user resolves initial calculation errors and confirms the correct values for both forces.
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A Mercedes-Benz 300SL (m = 1700 kg) is parked on a road that rises 20° above the horizontal.
(a) What is the magnitude of the normal force?
(b) What is the static frictional force that the ground exerts on the tires?


Homework Equations


FN=Wcos(theta)
Wsin(theta)=Framp
(at least that's what was given in lecutre)

The Attempt at a Solution


To find the weight using 1700kg*9.8, but when I plug that in, the computer program (gotta love these for homework assignments...) says no. I'm lost as to how to proceed.
Help would be greatly appreciated.
 
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Your method seems to be correct so I would recommend posting the numerical value your calculation gave you so we can compare. When taking the cos/sin did you have your calculator on degrees or on radians? What is the amount of significant figures asked etc etc.
 
I've got my calculator on degrees. The program didn't define any sig figs (it usually takes whatever is put in), and the units are given. Trying to find Newtons for both.

1700*9.8=16660=W

FN= 16660cos(20)=15655.27

Framp=16660sin(20)=5698.05
 
Nevermind about the silly program...it was my fingers missing numbers on my calc. The numbers that I gave in the reply were the right ones. Thank you so much though!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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