Metacentric height

[logearav]

Homework Statement

In a ship of 10000 tons, the breadth of whose deck is 20 m, a mass of 50 tons is moved from one side to the other causing the bob of a plumb line 10 m long to move over 20 cm. Find the metacentric height?

Homework Equations

The Attempt at a Solution

I don't know whether this is correct.
Metacentric height = wx/Wθ
Where w = 50 ton, x = 10 m, W = 10000 tons. I don't know how to calculate θ? Is it sinθ or tanθ? Because for small angles both sinθ and cosθ is equal to θ.
Revered members can help

 

[Spinnor]

You wrote,

I don't know how to calculate θ? Is it sinθ or tanθ? Because for small angles both sinθ and cosθ is equal to θ.

^^^ you mean tanθ and not cosθ

They give you the info, 10m plumb line moves .2m, tanθ = .2/10 , θ = .2/10

See,

http://www.marineinsight.com/misc/n...t-determining-metacentric-height-of-the-ship/

 

[logearav]

Thanks Spinnor, i meant tanθ, which i erroneously entered as cos. So θ = .02.
Do the formula i used to arrive at the solution is correct?