Metric Spaces, Triangle Inequality

cwatki14
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I have the following question on metric spaces

Let (X,d) be a metric space and x1,x2,...,xn ∈ X. Show that
d(x1, xn) ≤ d(x1, x2) + · · · + d(xn−1, xn2 ),
and
d(x1, x3) ≥ |d(x1, x2) − d(x2, x3)|.

So the first part is simply a statement of the triangle inequality. However, the metric isn't given. How do I prove the triangle equality for a metric space when the metric isn't given?

For the second part, I attempted a few solns using a typical approach with the triangle inequality, however none of them seemed to be working... Any ideas?
 
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cwatki14 said:
I have the following question on metric spaces

Let (X,d) be a metric space and x1,x2,...,xn ∈ X. Show that
d(x1, xn) ≤ d(x1, x2) + · · · + d(xn−1, xn2 ),
and
d(x1, x3) ≥ |d(x1, x2) − d(x2, x3)|.

So the first part is simply a statement of the triangle inequality. However, the metric isn't given. How do I prove the triangle equality for a metric space when the metric isn't given?
It's not exactly a statement of the triangle inequality. The triangle inequality is a relationship between 3 points in X. You need to show that the statement above, which involves n points in X, holds.
For the second part, I attempted a few solns using a typical approach with the triangle inequality, however none of them seemed to be working... Any ideas?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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