Midterm Q1b: Signal Transformation Solutions

AI Thread Summary
The discussion centers on the confusion regarding the solution to question 1b of the midterm, specifically about signal transformation. The key issue is the misunderstanding of how flipping and shifting operations interact in the context of the function h(t). It is clarified that computing h(y(t)) with y(t) = -t-2 requires a different approach than simply flipping the previous result. The correct method involves shifting by 4 after applying the negative transformation, rather than flipping the function directly. Understanding these transformations is crucial for accurately solving the problem.
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In question 1b of the midterm in the pdf attached below, I don't understand why the solution should be what it stated in the other pdf attached rather than what I did in the picture, which basically flips 1a along y-axis.
 

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Flipping about the axis does not apply to the shift.
You have h(t), and you want to compute h(y(t)) where y(t) = -t-2.
h(-y(t)) \neq h(y(-t))
The former is what you did, which is to compute y(t+2) and then flip, but that gives you y(-t+2), so then you need to shift by 4 to get y(-t-2).
 

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