Millikan oil drop experiment potential difference

AI Thread Summary
To find the potential difference between the plates in a Millikan oil drop experiment with an electric field of 1.92 x 10^5 N/C and a separation of 1.5 cm, the relationship between electric field (E), potential difference (V), and distance (d) is used. The formula V = E * d can be applied, where d must be converted to meters. The mass of the oil drop is necessary to calculate the charge (q) using the equation mg = qE, but mass is not provided in this scenario. Understanding the relationship between electric field strength and potential difference is crucial for solving the problem. The discussion emphasizes the need for mass to determine charge and ultimately the potential difference.
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Homework Statement


in a Millikan oil drop experiment, a uniform electric filed of 1.92 x 10^5 N/C is maintained in a region between two plates separated by 1.5 cm. Find the potential difference between the plates.


Homework Equations


mg = q x E


The Attempt at a Solution


in order to find the q and hence find the voltage/potential you need to have mass. there is no mass given. I assume once you have mass you get q and from there you can find voltage using k(q/r)
 
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To find V, the pd between the plates:
In a uniform electric field between parallel plates, the field can be calculated from the potential gradient. You have the field strength given and you know the plate separation.
Does this help?
 

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