asleight
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Homework Statement
A circular steel wire 1.91m long must stretch no more than 0.0024m when a tensile force of 450N is applied to each end of the wire.
What minimum diameter is required for the wire?
Homework Equations
p=\frac{F}{\Delta A}
The Attempt at a Solution
I can't seem to solve for this at all. I've tried applying a volume to this exercise:
A=V/l, where l is the length, then dA=\sqrt{dV/l-Vdl/l^2}...
p=\frac{F}{\Delta A}=\frac{F}{\sqrt{dV/l-Vdl/l^2}}. This didn't work, as far as I remember...