Minimum Force for Moving a Sled on a Horizontal Surface

  • Thread starter Thread starter tutojean
  • Start date Start date
  • Tags Tags
    Force Minimum
AI Thread Summary
To determine the minimum force required to keep a sled moving on a horizontal surface with a kinetic friction coefficient of 0.20 and a mass of 2 slugs, the frictional force is calculated using the formula fs = μs(N), where N is the normal force. The normal force for a sled on a flat surface is equal to the weight, which can be calculated as mass times gravity (2 slugs x 32 ft/s²). This results in a frictional force of 12.8 pounds. The discussion also clarifies that the unit of force is in pounds when using slugs. Understanding these calculations is essential for solving similar physics problems.
tutojean
Messages
6
Reaction score
0

Homework Statement


A sled is pulled over a horizontal surface where the kinetic coefficient of friction is .20. What is the minimum force necessary to keep the sled moving if its mass is 2 slugs?


Homework Equations


fs = Ns(mg)


The Attempt at a Solution


fs = (.20) (2 slugs) (32)
=12.8

This problem has got me stumped. Please help! Thank You.
 
Physics news on Phys.org
What is the unit of fs?
 
I assume 12.8 N
 
tutojean said:
I assume 12.8 N
Unit force is N if mass is in kg.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Pulling a sled across snow with a rope at an angle
Replies
8
Views
4K
Acceleration = (Force of boy on sled - Force of friction)/Mass of sled
Replies
3
Views
2K
Work and Kinetic Energy of a Sled
Replies
4
Views
5K
Kinetic Energy and Newton Forces - distance/speed
Replies
3
Views
2K
Frictional Forces and Coefficients of Friction [Need help]
Replies
1
Views
1K
Friction between sled and rider
Replies
7
Views
2K
Calculating Work and Change in Thermal Energy
Replies
2
Views
2K
How to find the minimum horizontal force?
Replies
11
Views
20K
Tension and acceleration of a sled?
Replies
3
Views
5K
Solving Force and Motion: Pulling 25.0 kg Sled 25m
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top