Minimum force necessary to push out a cork

AI Thread Summary
To determine the minimum force required to push out a cork from a U-tube with unequal diameters, the initial force needed to remove the cork from the narrow arm is 16 N. The pressure in the narrow arm is calculated using the formula p1 = f1/(π*r^2), while the pressure in the wider arm is p2 = f2/(π*(2r)^2). Setting the pressures equal leads to the equation f1/(π*r^2) = f2/(π*4r^2), simplifying to f2 = 4*f1. This results in f2 being 64 N, correcting the initial miscalculation of 32 N. The discussion emphasizes the importance of careful dimensional analysis to avoid errors.
drunknfox
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Homework Statement


2 arms of a u-tube are not identical, one having twice the diameter of the other. a cork in the narrow arm requires a force of 16n to remove it. the tube is filled with water and the wide arm is fitted with a piston. the min force that must be applied to the piston to push out cork is?


Homework Equations


p=f/a


The Attempt at a Solution


p1=f1/(pi*r^2), p2=f/pi*2r^2, p1=p2, f1/(pi*r^2)=f2/(pi*2r^2)...f2=(pi*r^2)*f1/(pi*r^2) which gives me 32. The answer is actually 64. What am i missing?
 
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hi drunknfox! :smile:

(have a pi: π and try using the X2 icon just above the Reply box :wink:)
drunknfox said:
p1=f1/(pi*r^2), p2=f/pi*2r^2, p1=p2, f1/(pi*r^2)=f2/(pi*2r^2)...f2=(pi*r^2)*f1/(pi*r^2) which gives me 32. The answer is actually 64. What am i missing?

it isn't π*2r2 :redface:

(and using a dimensional argument would be much quicker, and less likely to lead to a mistake)
 
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