Mixing different temperatures of water ?

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SUMMARY

The final temperature when mixing 1 liter of water at 20 degrees Celsius with 2 liters at 40 degrees Celsius can be calculated using the equation Q = mcΔT. By setting the heat lost by the hotter water equal to the heat gained by the cooler water, the final temperature T can be determined. The solution involves equating the heat changes of both water masses and solving for T, which will yield a temperature between 20 and 40 degrees Celsius.

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"What would be the final temperature if you mixed a liter of 20 degrees C water with 2 liters of 40 degrees C water?"

My teacher assigned us several problems like these without bothering to explain them. I have a hunch that they are embarrassingly simple to complete, but I know not how to find the solutions. The only equation we've been given to this point is Q = mcΔT.

ANY help would be appreciated. Thanks in advance.
 
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Q is the heat energy. The amount of heat coming out of the hotter water is equal to the amount of heat going into the cooler water. Suppose the final temperature is T (somewhere between 20 and 40 degrees). Find the change in heat for each mass of water and equate them. Then solve for T.
 

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