Chemistry How many bonds and pi bonds does glycine have?

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Glycine has sp3 hybridization at both nitrogen atoms and sp2 hybridization at the carbon atom involved in the double bond with oxygen. The total number of bonds in glycine is 10, which includes single and double bonds counted appropriately. There is only one pi bond present, which is formed by the double bond between carbon and oxygen. The oxygen's lone pairs are held in sp2 hybridized orbitals, leaving one unhybridized p orbital available for the pi bond. Understanding the hybridization and orbital overlap is crucial for accurately determining the bonding structure of glycine.
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[SOLVED] molecular orbital model

I have a few quick questions:

consider the structure of glycine
a) indicate the hybridizations at each N and C atom in the molecule?
I got sp3, sp3, and sp2

I don't have a problem with that question

b) what is the total number of bonds in the molecule? Not quite sure what this means do i just add them up counting the double bond as 2? So any help would be appreciated

c) what is the total number of pi bonds in the molecule? I think it's 1 because the oxygen at the end has 2p orbitals holding just lone pairs

My basic problem is b. and what do I? Any help would be appreciated.
 
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Hi,

yes count double bond as 2

1 double bond = 1 pi bond + 1 sigma bond

only 1 double bond so only 1 pi bond (its the C=O) that has the pi bond, not the O in (C-O) at the end.
 
Okay so i looked up the answer for b) and it said 10. How is it 10? Did i draw it wrong or I just can't count? And about c) i thought their was a pi bond between the C and O because they each have an empty p orbital? Or that's wrong b/c the p orbitals on the O are holding lone pairs?

Thanks for answering
 
Um yea ignore the question for b) I actually added wrong:redface:
 
a pi bond is the SIDE-BY-SIDE overlap of 2 p orbitals (one from O, one from C) that each have 1 electron in them. These p orbitals are unhybridized.


The orbitals that are holding the lone pairs on O are HYBRIDIZED sp2 orbitals. They are not p orbitals that are empty.
 
but what about the left over p orbital? Like if it's sp2 hydridized there should be a p left right?
 
ahh I am sorry. I was trying to overlap a p orbital twice. Thank You
 
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