Moment of inertia of a flywheel

AI Thread Summary
The discussion revolves around calculating the moment of inertia of a flywheel given a decrease in kinetic energy of 750 J as its angular velocity changes from 870 rev/min to 410 rev/min. The key equation used is I = 2K / (ω_i² - ω_f²), where K represents kinetic energy and ω represents angular velocity in radians per second. The initial and final angular velocities were converted correctly, but there was confusion about assuming the final kinetic energy (K_f) to be zero. Ultimately, the correct moment of inertia calculated was 0.232 kg*m², emphasizing that the change in kinetic energy is the critical factor rather than the absolute values of K_i and K_f. Understanding the relationship between kinetic energy and angular velocity is essential for solving such problems.
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[SOLVED] moment of inertia

Homework Statement


The flywheel of a gasoline engine is required to give up 750 J of kinetic energy while its angular velocity decreases from 870 rev/min to 410 rev/min.

What moment of inertia is required?

Homework Equations



I=\frac{2K}{\omega^{2}}

The Attempt at a Solution



I'm not sure how to derive the rad/sec used in this equation. I've converted both 870 rev/min and 410 rev/min to radians before attempting the problem (91.1 rad/sec and 42.9 rad/sec respectively). I've tried taking the difference between the two, then attempting the average, then just using the final radial velocity and ignoring the initial. I'm not sure what to do at the moment. Can anyone help?
 
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Well they're saying "give up" 750 joules of KE. So you don't actually know any absolute kinetic energies. You know there is a Ki, and that Kf=Ki-750J, you know Ki corresponds with 870rpm and Kf corresponds with 410 rpm, and that is all you're given to work with
 
You started on the right track but got off on the wrong foot.

<br /> \begin{aligned}<br /> K_i &amp;= \frac 1 2 I \omega_i^2 \\[4pt]<br /> K_f &amp;= \frac 1 2 I \omega_f^2 \\<br /> &amp;\Rightarrow \\<br /> K_i-K_f &amp;= \frac 1 2 I (\omega_i^2 - \omega_f^2)<br /> \end{aligned}

You can take it from here.
 
I did something, but I'm still not sure I understand it, but it seemed to work.

If I assume K_{f} is 0, then I can set up the problem like so:

K_{i}=\frac{1}{2}I(\omega_{i}^{2}-\omega_{f}^{2})

Solving for I, I get\frac{2K_{i}}{(\omega_{i}^{2}-\omega_{f}^{2})}=I

Plug and chug and got .232 kg*m^2, which is the correct answer.

What I don't understand is why K_{f} is 0.
 
You cannot assume K_f is zero. You are given the change in angular kinetic energy. The problem statement says exactly what K_i-K_f is: 750 joules.
 
So in other words. What K initial and K final are is not important, because the change in kinetic energy is already given in the problem?
 
yeah
 
^_^; man I feel stupid now. Well, anyway thanks!
 
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