Moment vector expression to magnitude of moment

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Homework Help Overview

The discussion revolves around finding the magnitude and angle of a moment vector given as -2.8i - 1.53j + 2.24k, with a force tension of 2.4 kN. The subject area is vector analysis in physics.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of the cross product and the application of sine and cosine functions to vectors. There is an attempt to recall the method for calculating the magnitude of the vector, with some expressing uncertainty about vector operations.

Discussion Status

Some participants provide guidance on calculating the magnitude of the vector by suggesting the method of squaring the components, adding them, and taking the square root. However, there is no explicit consensus on the approach to finding the angle.

Contextual Notes

One participant notes a lack of recent experience with vectors, indicating potential gaps in understanding the topic. The discussion reflects a mix of attempts and clarifications without a complete resolution.

kleeds
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Homework Statement


find the magnitude and angle of the moment

moment=-2.8i-1.53j+2.24k

force tension=2.4 kN

Homework Equations


rxf=rfsin(theta)

The Attempt at a Solution


i used the cross product to get i j and k
tried sin and cos of vectors but didnt work.
inverse tan of vectors won't give close to correct angles
 
Last edited:
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Welcome to PF!

As far I as I can tell, the first part of the question is simply asking what the magnitude of the given vector is. You have all three components of the vector.

What is the expression for the magnitude of a vector in terms of its components?
 
I have no idea. The last time i did vectors at least six months ago.
 
nevermind you square them all, add them, then take the square root.
 
kleeds said:
nevermind you square them all, add them, then take the square root.

Yeah.
 

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