Moments - Balancing a weighted meter stick

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A meter stick balances at the 49.2cm mark on a fulcrum, and when a 46.0g mass is added at the 14.7cm mark, the fulcrum shifts to 38.7cm for balance. To solve for the mass of the meter stick, it's essential to analyze the moments by drawing free body diagrams (FBDs) for both scenarios. The sum of the torques around the fulcrum must equal zero when the system is balanced. After applying these principles, the original poster successfully determined the mass of the meter stick. Understanding moments and torque is crucial for solving such balance problems.
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Moments -- Balancing a weighted meter stick

A meter stick is found to balance at the 49.2cm mark when placed on a fulcrum. When a 46.0g mass is attached at the 14.7cm mark, the fulcrum must be moved to the 38.7cm mark for balance. What is the mass of the meter stick?

I know I have to use moments but I don't know where to start. Any help would be appreciated.
 
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alexmahone said:
A meter stick is found to balance at the 49.2cm mark when placed on a fulcrum. When a 46.0g mass is attached at the 14.7cm mark, the fulcrum must be moved to the 38.7cm mark for balance. What is the mass of the meter stick?

I know I have to use moments but I don't know where to start. Any help would be appreciated.

Draw FBDs for the two situations, and show the torques about the fulcrum. When the stick is balanced, what must the sum of the torques be?

(BTW, I will add some more descriptive words to your thread title -- 1-word titles are not generally allowed in the technical PF forums.)
 


berkeman said:
Draw FBDs for the two situations, and show the torques about the fulcrum. When the stick is balanced, what must the sum of the torques be?

(BTW, I will add some more descriptive words to your thread title -- 1-word titles are not generally allowed in the technical PF forums.)

Thanks. Once I drew the FBDs, I got the answer. :D
 


Sweet! :smile:
 
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