Momentum and velocity/position vectors

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Two particles, A and B, collide and coalesce at the origin, with A having a mass of m and velocity of 2i + 3j, and B having a mass of 3m and velocity of 6i - 5j. The velocity of the coalesced particle is determined to be 5i - 3j, with a kinetic energy loss of 30 joules during the collision. The center of mass's position and velocity are calculated using the total linear momentum and mass of the system. The discussion highlights confusion around deriving position vectors from velocity vectors, especially for times before the collision. Overall, the participants clarify calculations and seek further assistance on specific steps in the problem-solving process.
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Homework Statement



I have two particles moving on a smooth horizontal table. The first, A, has mass m and the second, B, has mass 3m. A has velocity 2i + 3j and B has velocity 6i - 5j. They collide at the origin at t=0 and coalesce.

I have to 1) determine the velocity of the coalesced particle after the collision; 2) determine the amount of energy lost in the collision; 3) find expressions for rA(t) and rB(t) at time t<0; 4) find the position vector of the centre of mass of the system before the collision; 5) determine the velocity of the centre of mass; 6) find the position vector of the coalesced particles at time t>0 after the collision; and 7) comment on the answers to parts 3)-6)

Homework Equations



I've used the following: 1) Total linear momentum of system P=mv and found P of A is 2mi + 3mj and P of B is 18mi - 15mj, so using the Principle of conservation of momentum, I found v of coalesced particle to be 5i - 3j

2) kinetic energy=1/2mmodv2 and KE before impact is 98m and after is 68m, so loss is 30 joules.

4) rG=\Sigmamiri all divided by total mass...when I finally find the position vectors!

5) Velocity of the centre of mass=total linear momentum of the system...I think.

6) With position vectors for A and B, I'm not sure what to do here: add them, since the particles coalesce?

The Attempt at a Solution



3) My problem is from 3) onwards. I'm pretty sure I can figure out the rest of it once I have 3). I can't work out how to get from the velocity vectors to position vectors. I thought of integrating and using t=0 r=0 to find a particular solution, but that seems to just leave me with rA(t)=2ti + 3tj and rB(t)=6ti - 5tj, which just doesn't seem to make sense.
 
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Welcome to PF deborahlane and thanks for taking the time to lay out your problem properly.
deborahlane said:
1) Total linear momentum of system P=mv and found P of A is 2mi + 3mj and P of B is 18mi + 15mj, so using the Principle of conservation of momentum, I found v of coalesced particle to be 5i - 3j
Correct, just a small typo highlighted in red.
deborahlane said:
2) kinetic energy=1/2mmodv2 and KE before impact is 98m and after is 68m, so loss is 30 joules.
Looks good to me.

Okay for number three:
deborahlane said:
3) 'm pretty sure I can figure out the rest of it once I have 3). I can't work out how to get from the velocity vectors to position vectors. I thought of integrating and using t=0 r=0 to find a particular solution, but that seems to just leave me with rA(t)=2ti + 3tj and rB(t)=6ti - 5tj, which just doesn't seem to make sense.
You're almost correct here. Notice that you are dealing with the case when t<0, i.e. negative time.
deborahlane said:
4) rG=\Sigmamiri all divided by total mass...when I finally find the position vectors!
Again looks good.
deborahlane said:
5) Velocity of the centre of mass=total linear momentum of the system...I think.
Don't forget to divide by the total mass!
deborahlane said:
6) With position vectors for A and B, I'm not sure what to do here: add them, since the particles coalesce?
Consider the centre of mass of the system, what can you say about the velocity of the COM before and after the collision?
 
Thanks, Hootenanny. Your suggestions have been very helpful! Sadly, though, I'm still lost on part 3)! I'll give it some more thought and see what more advice others can give, and what I can work out from your help!
 
deborahlane said:
Thanks, Hootenanny. Your suggestions have been very helpful! Sadly, though, I'm still lost on part 3)! I'll give it some more thought and see what more advice others can give, and what I can work out from your help!
Scrap my previous comment regarding question (3), your answer is entirely correct! Sorry for the confusion.
 
Hootenanny said:
Scrap my previous comment regarding question (3), your answer is entirely correct! Sorry for the confusion.

Great! :)
 
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